131011130104401 has 32 divisors (see below), whose sum is σ = 180704550570880. Its totient is φ = 84363568809984.

The previous prime is 131011130104391. The next prime is 131011130104403. The reversal of 131011130104401 is 104401031110131.

It is not a de Polignac number, because 131011130104401 - 2¹⁰ = 131011130103377 is a prime.

It is a super-2 number, since 2×131011130104401² (a number of 29 digits) contains 22 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (131011130104403) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 255448641 + ... + 255960993.

It is an arithmetic number, because the mean of its divisors is an integer number (5647017205340).

Almost surely, 2^{131011130104401} is an apocalyptic number.

It is an amenable number.

131011130104401 is a deficient number, since it is larger than the sum of its proper divisors (49693420466479).

131011130104401 is a wasteful number, since it uses less digits than its factorization.

131011130104401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 529105.

The product of its (nonzero) digits is 144, while the sum is 21.

Adding to 131011130104401 its reverse (104401031110131), we get a palindrome (235412161214532).

The spelling of 131011130104401 in words is "one hundred thirty-one trillion, eleven billion, one hundred thirty million, one hundred four thousand, four hundred one".