131011142344033 has 16 divisors (see below), whose sum is σ = 149896642998784. Its totient is φ = 112168110113280.

The previous prime is 131011142344007. The next prime is 131011142344037. The reversal of 131011142344033 is 330443241110131.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131011142344033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131011142343986 and 131011142344004.

It is not an unprimeable number, because it can be changed into a prime (131011142344037) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22514053 + ... + 27729133.

It is an arithmetic number, because the mean of its divisors is an integer number (9368540187424).

Almost surely, 2^{131011142344033} is an apocalyptic number.

It is an amenable number.

131011142344033 is a deficient number, since it is larger than the sum of its proper divisors (18885500654751).

131011142344033 is a wasteful number, since it uses less digits than its factorization.

131011142344033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5219152.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 131011142344033 its reverse (330443241110131), we get a palindrome (461454383454164).

The spelling of 131011142344033 in words is "one hundred thirty-one trillion, eleven billion, one hundred forty-two million, three hundred forty-four thousand, thirty-three".