Base | Representation |
---|---|
bin | 11101110010011101101000… |
… | …100110011101110101100000 |
3 | 122011212112122202201102210110 |
4 | 131302131220212131311200 |
5 | 114132441304420002112 |
6 | 1142345404331331320 |
7 | 36411146144625516 |
oct | 3562355046356540 |
9 | 564775582642713 |
10 | 131011142344032 |
11 | 38820571444105 |
12 | 1283aa065b0b40 |
13 | 58143b40c65b2 |
14 | 244cd8a36a4b6 |
15 | 1022d7911a13c |
hex | 77276899dd60 |
131011142344032 has 96 divisors (see below), whose sum is σ = 346252125945600. Its totient is φ = 43372355212800.
The previous prime is 131011142344007. The next prime is 131011142344037. The reversal of 131011142344032 is 230443241110131.
It is a tau number, because it is divible by the number of its divisors (96).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131011142344037) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 70592719 + ... + 72424817.
It is an arithmetic number, because the mean of its divisors is an integer number (3606792978600).
Almost surely, 2131011142344032 is an apocalyptic number.
131011142344032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131011142344032, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (173126062972800).
131011142344032 is an abundant number, since it is smaller than the sum of its proper divisors (215240983601568).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131011142344032 is a wasteful number, since it uses less digits than its factorization.
131011142344032 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1837196 (or 1837188 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 30.
Adding to 131011142344032 its reverse (230443241110131), we get a palindrome (361454383454163).
The spelling of 131011142344032 in words is "one hundred thirty-one trillion, eleven billion, one hundred forty-two million, three hundred forty-four thousand, thirty-two".
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