131011202023 has 4 divisors (see below), whose sum is σ = 141088986808. Its totient is φ = 120933417240.

The previous prime is 131011201949. The next prime is 131011202029. The reversal of 131011202023 is 320202110131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131011202023 is a prime.

It is a super-2 number, since 2×131011202023² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131011201988 and 131011202006.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131011202029) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5038892373 + ... + 5038892398.

It is an arithmetic number, because the mean of its divisors is an integer number (35272246702).

Almost surely, 2^131011202023 is an apocalyptic number.

131011202023 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

131011202023 is a deficient number, since it is larger than the sum of its proper divisors (10077784785).

131011202023 is a wasteful number, since it uses less digits than its factorization.

131011202023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10077784784.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 131011202023 its reverse (320202110131), we get a palindrome (451213312154).

The spelling of 131011202023 in words is "one hundred thirty-one billion, eleven million, two hundred two thousand, twenty-three".