Base | Representation |
---|---|
bin | 10011000100001000110… |
… | …100100001100100111111 |
3 | 11122020122000202200201022 |
4 | 103010020310201210333 |
5 | 132431102412341111 |
6 | 2441505124334355 |
7 | 163436551601435 |
oct | 23041064414477 |
9 | 4566560680638 |
10 | 1310113012031 |
11 | 46568570587a |
12 | 191aaa2443bb |
13 | 9670a332c25 |
14 | 475a4728d55 |
15 | 2412bba82db |
hex | 13108d2193f |
1310113012031 has 4 divisors (see below), whose sum is σ = 1311732435600. Its totient is φ = 1308493588464.
The previous prime is 1310113011937. The next prime is 1310113012123. The reversal of 1310113012031 is 1302103110131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1310113012031 - 210 = 1310113011007 is a prime.
It is a super-2 number, since 2×13101130120312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1310113512031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 809710571 + ... + 809712188.
It is an arithmetic number, because the mean of its divisors is an integer number (327933108900).
Almost surely, 21310113012031 is an apocalyptic number.
1310113012031 is a deficient number, since it is larger than the sum of its proper divisors (1619423569).
1310113012031 is an equidigital number, since it uses as much as digits as its factorization.
1310113012031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1619423568.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 1310113012031 its reverse (1302103110131), we get a palindrome (2612216122162).
The spelling of 1310113012031 in words is "one trillion, three hundred ten billion, one hundred thirteen million, twelve thousand, thirty-one".
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