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1310113121311 = 2356961440057
BaseRepresentation
bin10011000100001000110…
…100111100010000011111
311122020122000222020121201
4103010020310330100133
5132431102424340221
62441505130540331
7163436552535151
oct23041064742037
94566560866551
101310113121311
1146568577a995
12191aaa2976a7
139670a3708a7
14475a4756ad1
152412bbca891
hex13108d3c41f

1310113121311 has 4 divisors (see below), whose sum is σ = 1367074561392. Its totient is φ = 1253151681232.

The previous prime is 1310113121299. The next prime is 1310113121327. The reversal of 1310113121311 is 1131213110131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1310113121311 - 225 = 1310079566879 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310113127311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28480720006 + ... + 28480720051.

It is an arithmetic number, because the mean of its divisors is an integer number (341768640348).

Almost surely, 21310113121311 is an apocalyptic number.

1310113121311 is a deficient number, since it is larger than the sum of its proper divisors (56961440081).

1310113121311 is an equidigital number, since it uses as much as digits as its factorization.

1310113121311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56961440080.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 1310113121311 its reverse (1131213110131), we get a palindrome (2441326231442).

The spelling of 1310113121311 in words is "one trillion, three hundred ten billion, one hundred thirteen million, one hundred twenty-one thousand, three hundred eleven".

Divisors: 1 23 56961440057 1310113121311