13101132031 has 4 divisors (see below), whose sum is σ = 14108911432. Its totient is φ = 12093352632.

The previous prime is 13101132019. The next prime is 13101132043. The reversal of 13101132031 is 13023110131.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (13101132019) and next prime (13101132043).

It is a cyclic number.

It is not a de Polignac number, because 13101132031 - 2⁵ = 13101131999 is a prime.

It is a super-2 number, since 2×13101132031² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13101131996 and 13101132014.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13101132001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 503889681 + ... + 503889706.

It is an arithmetic number, because the mean of its divisors is an integer number (3527227858).

Almost surely, 2^13101132031 is an apocalyptic number.

13101132031 is a deficient number, since it is larger than the sum of its proper divisors (1007779401).

13101132031 is a wasteful number, since it uses less digits than its factorization.

13101132031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1007779400.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 13101132031 its reverse (13023110131), we get a palindrome (26124242162).

The spelling of 13101132031 in words is "thirteen billion, one hundred one million, one hundred thirty-two thousand, thirty-one".