Base | Representation |
---|---|
bin | 1011111010100101110001… |
… | …1100000001010100110101 |
3 | 1201101110111020020011220101 |
4 | 2332221130130001110311 |
5 | 3204122224440232013 |
6 | 43510335251234101 |
7 | 2521346655645364 |
oct | 276513434012465 |
9 | 51343436204811 |
10 | 13101201102133 |
11 | 41a1208524691 |
12 | 15771258a8931 |
13 | 740590286b81 |
14 | 33415c7c17db |
15 | 17abd40788dd |
hex | bea5c701535 |
13101201102133 has 4 divisors (see below), whose sum is σ = 13101650896140. Its totient is φ = 13100751308128.
The previous prime is 13101201102131. The next prime is 13101201102149. The reversal of 13101201102133 is 33120110210131.
13101201102133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 2475439662609 + 10625761439524 = 1573353^2 + 3259718^2 .
It is a cyclic number.
It is not a de Polignac number, because 13101201102133 - 21 = 13101201102131 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 13101201102133.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13101201102131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 224853310 + ... + 224911567.
It is an arithmetic number, because the mean of its divisors is an integer number (3275412724035).
Almost surely, 213101201102133 is an apocalyptic number.
It is an amenable number.
13101201102133 is a deficient number, since it is larger than the sum of its proper divisors (449794007).
13101201102133 is an equidigital number, since it uses as much as digits as its factorization.
13101201102133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 449794006.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 13101201102133 its reverse (33120110210131), we get a palindrome (46221311312264).
The spelling of 13101201102133 in words is "thirteen trillion, one hundred one billion, two hundred one million, one hundred two thousand, one hundred thirty-three".
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