131012133320041 has 4 divisors (see below), whose sum is σ = 136708313029632. Its totient is φ = 125315953610452.

The previous prime is 131012133319987. The next prime is 131012133320069. The reversal of 131012133320041 is 140023331210131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131012133320041 - 2⁷ = 131012133319913 is a prime.

It is a super-3 number, since 3×131012133320041³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131012133319988 and 131012133320015.

It is not an unprimeable number, because it can be changed into a prime (131012133350041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2848089854761 + ... + 2848089854806.

It is an arithmetic number, because the mean of its divisors is an integer number (34177078257408).

Almost surely, 2^{131012133320041} is an apocalyptic number.

It is an amenable number.

131012133320041 is a deficient number, since it is larger than the sum of its proper divisors (5696179709591).

131012133320041 is an equidigital number, since it uses as much as digits as its factorization.

131012133320041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5696179709590.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 131012133320041 its reverse (140023331210131), we get a palindrome (271035464530172).

The spelling of 131012133320041 in words is "one hundred thirty-one trillion, twelve billion, one hundred thirty-three million, three hundred twenty thousand, forty-one".