Base | Representation |
---|---|
bin | 11101110010011110100011… |
… | …101110001101100100110010 |
3 | 122011212122012220010110222201 |
4 | 131302132203232031210302 |
5 | 114133000322330332242 |
6 | 1142350051003053414 |
7 | 36411212550544342 |
oct | 3562364356154462 |
9 | 564778186113881 |
10 | 131012134230322 |
11 | 38820a30325a44 |
12 | 1283b04281126a |
13 | 5814511752667 |
14 | 244d041da4d22 |
15 | 1022dd62474b7 |
hex | 7727a3b8d932 |
131012134230322 has 4 divisors (see below), whose sum is σ = 196518201345486. Its totient is φ = 65506067115160.
The previous prime is 131012134230319. The next prime is 131012134230331. The reversal of 131012134230322 is 223032431210131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 69511421697201 + 61500712533121 = 8337351^2 + 7842239^2 .
It is a super-3 number, since 3×1310121342303223 (a number of 43 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32753033557579 + ... + 32753033557582.
Almost surely, 2131012134230322 is an apocalyptic number.
131012134230322 is a deficient number, since it is larger than the sum of its proper divisors (65506067115164).
131012134230322 is an equidigital number, since it uses as much as digits as its factorization.
131012134230322 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65506067115163.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 131012134230322 its reverse (223032431210131), we get a palindrome (354044565440453).
The spelling of 131012134230322 in words is "one hundred thirty-one trillion, twelve billion, one hundred thirty-four million, two hundred thirty thousand, three hundred twenty-two".
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