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13101220203121 = 78253916741939
BaseRepresentation
bin1011111010100101110110…
…0100111000101001110001
31201101110112120011121112101
42332221131210320221301
53204122244332444441
643510341212500401
72521350310211401
oct276513544705161
951343476147471
1013101220203121
1141a1218290526
12157713017a701
1374059421402b
14334161154801
1517abd5a9d231
hexbea5d938a71

13101220203121 has 4 divisors (see below), whose sum is σ = 13101237727600. Its totient is φ = 13101202678644.

The previous prime is 13101220203107. The next prime is 13101220203139. The reversal of 13101220203121 is 12130202210131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13101220203121 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13101220203161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7588431 + ... + 9153508.

It is an arithmetic number, because the mean of its divisors is an integer number (3275309431900).

Almost surely, 213101220203121 is an apocalyptic number.

It is an amenable number.

13101220203121 is a deficient number, since it is larger than the sum of its proper divisors (17524479).

13101220203121 is an equidigital number, since it uses as much as digits as its factorization.

13101220203121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17524478.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 13101220203121 its reverse (12130202210131), we get a palindrome (25231422413252).

The spelling of 13101220203121 in words is "thirteen trillion, one hundred one billion, two hundred twenty million, two hundred three thousand, one hundred twenty-one".

Divisors: 1 782539 16741939 13101220203121