13101220203161 has 2 divisors, whose sum is σ = 13101220203162. Its totient is φ = 13101220203160.

The previous prime is 13101220203157. The next prime is 13101220203163. The reversal of 13101220203161 is 16130202210131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6625187715136 + 6476032488025 = 2573944^2 + 2544805^2 .

It is a cyclic number.

It is not a de Polignac number, because 13101220203161 - 2² = 13101220203157 is a prime.

It is a super-2 number, since 2×13101220203161² (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 13101220203163, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (13101220203163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550610101580 + 6550610101581.

It is an arithmetic number, because the mean of its divisors is an integer number (6550610101581).

Almost surely, 2^{13101220203161} is an apocalyptic number.

It is an amenable number.

13101220203161 is a deficient number, since it is larger than the sum of its proper divisors (1).

13101220203161 is an equidigital number, since it uses as much as digits as its factorization.

13101220203161 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 13101220203161 its reverse (16130202210131), we get a palindrome (29231422413292).

The spelling of 13101220203161 in words is "thirteen trillion, one hundred one billion, two hundred twenty million, two hundred three thousand, one hundred sixty-one".