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1310123121103 = 12491048937647
BaseRepresentation
bin10011000100001001011…
…011000101100111001111
311122020122201210021202101
4103010021123011213033
5132431113004333403
62441510125135531
7163440033534106
oct23041133054717
94566581707671
101310123121103
1146569038a985
12191ab16ba5a7
139670c462324
14475a5bdb03d
152412ca0371d
hex131096c59cf

1310123121103 has 4 divisors (see below), whose sum is σ = 1311172060000. Its totient is φ = 1309074182208.

The previous prime is 1310123121091. The next prime is 1310123121107. The reversal of 1310123121103 is 3011213210131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1310123121103 - 213 = 1310123112911 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310123121107) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 524467575 + ... + 524470072.

It is an arithmetic number, because the mean of its divisors is an integer number (327793015000).

Almost surely, 21310123121103 is an apocalyptic number.

1310123121103 is a deficient number, since it is larger than the sum of its proper divisors (1048938897).

1310123121103 is a wasteful number, since it uses less digits than its factorization.

1310123121103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1048938896.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 1310123121103 its reverse (3011213210131), we get a palindrome (4321336331234).

The spelling of 1310123121103 in words is "one trillion, three hundred ten billion, one hundred twenty-three million, one hundred twenty-one thousand, one hundred three".

Divisors: 1 1249 1048937647 1310123121103