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131012314001323 = 697399187858477
BaseRepresentation
bin11101110010011110101110…
…011011111110111110101011
3122011212122200102101210102221
4131302132232123332332223
5114133001204341020243
61142350120504134511
736411220162560136
oct3562365633767653
9564778612353387
10131012314001323
1138821012851617
121283b092a67437
13581453ca76231
14244d05bbdd21d
151022de6e07bed
hex7727ae6fefab

131012314001323 has 4 divisors (see below), whose sum is σ = 131012502557200. Its totient is φ = 131012125445448.

The previous prime is 131012314001297. The next prime is 131012314001357. The reversal of 131012314001323 is 323100413210131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131012314001323 - 213 = 131012313993131 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131012314001383) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93231840 + ... + 94626637.

It is an arithmetic number, because the mean of its divisors is an integer number (32753125639300).

Almost surely, 2131012314001323 is an apocalyptic number.

131012314001323 is a deficient number, since it is larger than the sum of its proper divisors (188555877).

131012314001323 is an equidigital number, since it uses as much as digits as its factorization.

131012314001323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 188555876.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 131012314001323 its reverse (323100413210131), we get a palindrome (454112727211454).

The spelling of 131012314001323 in words is "one hundred thirty-one trillion, twelve billion, three hundred fourteen million, one thousand, three hundred twenty-three".

Divisors: 1 697399 187858477 131012314001323