13101240440133 has 12 divisors (see below), whose sum is σ = 19746797185440. Its totient is φ = 8354414193576.

The previous prime is 13101240440047. The next prime is 13101240440143. The reversal of 13101240440133 is 33104404210131.

13101240440133 is a `hidden beast` number, since 1 + 3 + 10 + 1 + 240 + 4 + 401 + 3 + 3 = 666.

It is not a de Polignac number, because 13101240440133 - 2²⁰ = 13101239391557 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13101240440097 and 13101240440106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13101240440143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 31645508103 + ... + 31645508516.

It is an arithmetic number, because the mean of its divisors is an integer number (1645566432120).

Almost surely, 2^{13101240440133} is an apocalyptic number.

It is an amenable number.

13101240440133 is a deficient number, since it is larger than the sum of its proper divisors (6645556745307).

13101240440133 is a wasteful number, since it uses less digits than its factorization.

13101240440133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 63291016648 (or 63291016645 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 27.

Adding to 13101240440133 its reverse (33104404210131), we get a palindrome (46205644650264).

The spelling of 13101240440133 in words is "thirteen trillion, one hundred one billion, two hundred forty million, four hundred forty thousand, one hundred thirty-three".