13101244341001 has 4 divisors (see below), whose sum is σ = 13102014521104. Its totient is φ = 13100474160900.

The previous prime is 13101244340927. The next prime is 13101244341043. The reversal of 13101244341001 is 10014344210131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13101244341001 - 2⁹ = 13101244340489 is a prime.

It is a super-2 number, since 2×13101244341001² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13101244341061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 385064535 + ... + 385098556.

It is an arithmetic number, because the mean of its divisors is an integer number (3275503630276).

Almost surely, 2^{13101244341001} is an apocalyptic number.

It is an amenable number.

13101244341001 is a deficient number, since it is larger than the sum of its proper divisors (770180103).

13101244341001 is an equidigital number, since it uses as much as digits as its factorization.

13101244341001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 770180102.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 13101244341001 its reverse (10014344210131), we get a palindrome (23115588551132).

The spelling of 13101244341001 in words is "thirteen trillion, one hundred one billion, two hundred forty-four million, three hundred forty-one thousand, one".