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13101253423143 = 334211127651471
BaseRepresentation
bin1011111010100101111110…
…0011100111000000100111
31201101110121212200100211120
42332221133203213000213
53204122331334020033
643510344400505023
72521351162450644
oct276513743470047
951343555610746
1013101253423143
1141a1235010196
12157713b31b173
1374059b075852
14334165720dcb
1517abd89611b3
hexbea5f8e7027

13101253423143 has 8 divisors (see below), whose sum is σ = 17468848640256. Its totient is φ = 8733913577400.

The previous prime is 13101253423123. The next prime is 13101253423157. The reversal of 13101253423143 is 34132435210131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13101253423143 - 26 = 13101253423079 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13101253423123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 63723103 + ... + 63928368.

It is an arithmetic number, because the mean of its divisors is an integer number (2183606080032).

Almost surely, 213101253423143 is an apocalyptic number.

13101253423143 is a deficient number, since it is larger than the sum of its proper divisors (4367595217113).

13101253423143 is a wasteful number, since it uses less digits than its factorization.

13101253423143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 127685685.

The product of its (nonzero) digits is 25920, while the sum is 33.

Adding to 13101253423143 its reverse (34132435210131), we get a palindrome (47233688633274).

The spelling of 13101253423143 in words is "thirteen trillion, one hundred one billion, two hundred fifty-three million, four hundred twenty-three thousand, one hundred forty-three".

Divisors: 1 3 34211 102633 127651471 382954413 4367084474381 13101253423143