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13101302101103 = 36433335959691
BaseRepresentation
bin1011111010100110001001…
…1101010011010001101111
31201101110202021021110102222
42332221202131103101233
53204122431314213403
643510353300105555
72521352323301126
oct276514235232157
951343667243388
1013101302101103
1141a125a538707
1215771536952bb
137405a818a288
1433416bd92abd
1517abdcd79338
hexbea6275346f

13101302101103 has 4 divisors (see below), whose sum is σ = 13101338425128. Its totient is φ = 13101265777080.

The previous prime is 13101302101099. The next prime is 13101302101133. The reversal of 13101302101103 is 30110120310131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13101302101103 - 22 = 13101302101099 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13101302101133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17615513 + ... + 18344178.

It is an arithmetic number, because the mean of its divisors is an integer number (3275334606282).

Almost surely, 213101302101103 is an apocalyptic number.

13101302101103 is a deficient number, since it is larger than the sum of its proper divisors (36324025).

13101302101103 is an equidigital number, since it uses as much as digits as its factorization.

13101302101103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36324024.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 13101302101103 its reverse (30110120310131), we get a palindrome (43211422411234).

The spelling of 13101302101103 in words is "thirteen trillion, one hundred one billion, three hundred two million, one hundred one thousand, one hundred three".

Divisors: 1 364333 35959691 13101302101103