Base | Representation |
---|---|
bin | 1011111010100110001001… |
… | …1101010101101110011101 |
3 | 1201101110202021021222012110 |
4 | 2332221202131111232131 |
5 | 3204122431320024013 |
6 | 43510353300224233 |
7 | 2521352323342305 |
oct | 276514235255635 |
9 | 51343667258173 |
10 | 13101302111133 |
11 | 41a125a5451a5 |
12 | 157715369b079 |
13 | 7405a8191a02 |
14 | 33416bd96605 |
15 | 17abdcd7c2c3 |
hex | bea62755b9d |
13101302111133 has 4 divisors (see below), whose sum is σ = 17468402814848. Its totient is φ = 8734201407420.
The previous prime is 13101302111123. The next prime is 13101302111141. The reversal of 13101302111133 is 33111120310131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 13101302111133 - 212 = 13101302107037 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13101302111113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2183550351853 + ... + 2183550351858.
It is an arithmetic number, because the mean of its divisors is an integer number (4367100703712).
Almost surely, 213101302111133 is an apocalyptic number.
It is an amenable number.
13101302111133 is a deficient number, since it is larger than the sum of its proper divisors (4367100703715).
13101302111133 is an equidigital number, since it uses as much as digits as its factorization.
13101302111133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4367100703714.
The product of its (nonzero) digits is 162, while the sum is 21.
Adding to 13101302111133 its reverse (33111120310131), we get a palindrome (46212422421264).
The spelling of 13101302111133 in words is "thirteen trillion, one hundred one billion, three hundred two million, one hundred eleven thousand, one hundred thirty-three".
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