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131013220200000 = 26355218355367
BaseRepresentation
bin11101110010011111100100…
…011100110110111001000000
3122011212202000120120110022220
4131302133210130312321000
5114133010033332400000
61142350350435131040
736411251505253605
oct3562374434667100
9564782016513286
10131013220200000
1138821438328046
121283b2a6443a80
135814655730178
14244d1062d06ac
151022e4b75b1a0
hex7727e4736e40

131013220200000 has 168 divisors, whose sum is σ = 433271202243264. Its totient is φ = 34936858560000.

The previous prime is 131013220199977. The next prime is 131013220200007. The reversal of 131013220200000 is 2022310131.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is not an unprimeable number, because it can be changed into a prime (131013220200007) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 108577684 + ... + 109777683.

It is an arithmetic number, because the mean of its divisors is an integer number (2578995251448).

Almost surely, 2131013220200000 is an apocalyptic number.

131013220200000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131013220200000 is an abundant number, since it is smaller than the sum of its proper divisors (302257982043264).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131013220200000 is an frugal number, since it uses more digits than its factorization.

131013220200000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 218355407 (or 218355377 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 131013220200000 its reverse (2022310131), we get a palindrome (131015242510131).

The spelling of 131013220200000 in words is "one hundred thirty-one trillion, thirteen billion, two hundred twenty million, two hundred thousand".