13101340333003 has 4 divisors (see below), whose sum is σ = 14109135743248. Its totient is φ = 12093544922760.

The previous prime is 13101340332989. The next prime is 13101340333009. The reversal of 13101340333003 is 30033304310131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13101340333003 - 2¹⁷ = 13101340201931 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13101340333009) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 503897705103 + ... + 503897705128.

It is an arithmetic number, because the mean of its divisors is an integer number (3527283935812).

Almost surely, 2^{13101340333003} is an apocalyptic number.

13101340333003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

13101340333003 is a deficient number, since it is larger than the sum of its proper divisors (1007795410245).

13101340333003 is a wasteful number, since it uses less digits than its factorization.

13101340333003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1007795410244.

The product of its (nonzero) digits is 2916, while the sum is 25.

Adding to 13101340333003 its reverse (30033304310131), we get a palindrome (43134644643134).

The spelling of 13101340333003 in words is "thirteen trillion, one hundred one billion, three hundred forty million, three hundred thirty-three thousand, three".