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13101414011121 = 34367138003707
BaseRepresentation
bin1011111010100110100100…
…1000001101000011110001
31201101111001001212002010110
42332221221020031003301
53204123143441323441
643510412334451533
72521355152436322
oct276515110150361
951344031762113
1013101414011121
1141a1307724327
121577185063ba9
137405c5410b17
1433417cba4449
1517abe7ad2b16
hexbea6920d0f1

13101414011121 has 4 divisors (see below), whose sum is σ = 17468552014832. Its totient is φ = 8734276007412.

The previous prime is 13101414011087. The next prime is 13101414011129. The reversal of 13101414011121 is 12111041410131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13101414011121 - 239 = 12551658197233 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13101414011129) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2183569001851 + ... + 2183569001856.

It is an arithmetic number, because the mean of its divisors is an integer number (4367138003708).

Almost surely, 213101414011121 is an apocalyptic number.

It is an amenable number.

13101414011121 is a deficient number, since it is larger than the sum of its proper divisors (4367138003711).

13101414011121 is an equidigital number, since it uses as much as digits as its factorization.

13101414011121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4367138003710.

The product of its (nonzero) digits is 96, while the sum is 21.

Adding to 13101414011121 its reverse (12111041410131), we get a palindrome (25212455421252).

The spelling of 13101414011121 in words is "thirteen trillion, one hundred one billion, four hundred fourteen million, eleven thousand, one hundred twenty-one".

Divisors: 1 3 4367138003707 13101414011121