Base | Representation |
---|---|
bin | 111101000000100001… |
… | …1100101110101000001 |
3 | 110112011121101000110001 |
4 | 1322001003211311001 |
5 | 4121304120033441 |
6 | 140104225240001 |
7 | 12315440335150 |
oct | 1720103456501 |
9 | 415147330401 |
10 | 131014221121 |
11 | 50621126503 |
12 | 21484493001 |
13 | c47c050984 |
14 | 64ac079597 |
15 | 361be03731 |
hex | 1e810e5d41 |
131014221121 has 16 divisors (see below), whose sum is σ = 152640835200. Its totient is φ = 110124494208.
The previous prime is 131014221103. The next prime is 131014221139. The reversal of 131014221121 is 121122410131.
It is an interprime number because it is at equal distance from previous prime (131014221103) and next prime (131014221139).
It is a cyclic number.
It is not a de Polignac number, because 131014221121 - 217 = 131014090049 is a prime.
It is a super-2 number, since 2×1310142211212 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (131014231121) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 218890 + ... + 556723.
It is an arithmetic number, because the mean of its divisors is an integer number (9540052200).
Almost surely, 2131014221121 is an apocalyptic number.
It is an amenable number.
131014221121 is a deficient number, since it is larger than the sum of its proper divisors (21626614079).
131014221121 is an equidigital number, since it uses as much as digits as its factorization.
131014221121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 776088.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 131014221121 its reverse (121122410131), we get a palindrome (252136631252).
The spelling of 131014221121 in words is "one hundred thirty-one billion, fourteen million, two hundred twenty-one thousand, one hundred twenty-one".
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