Base | Representation |
---|---|
bin | 111101000000101100… |
… | …1101011001110100010 |
3 | 110112012000021010211212 |
4 | 1322001121223032202 |
5 | 4121312110313102 |
6 | 140104553310122 |
7 | 12315540466421 |
oct | 1720131531642 |
9 | 415160233755 |
10 | 131020010402 |
11 | 50624420036 |
12 | 21486405342 |
13 | c4802c9a98 |
14 | 64acb452b8 |
15 | 361c698c52 |
hex | 1e8166b3a2 |
131020010402 has 4 divisors (see below), whose sum is σ = 196530015606. Its totient is φ = 65510005200.
The previous prime is 131020010371. The next prime is 131020010411. The reversal of 131020010402 is 204010020131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 204010020131 = 95791 ⋅2129741.
It can be written as a sum of positive squares in only one way, i.e., 121898041321 + 9121969081 = 349139^2 + 95509^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32755002599 + ... + 32755002602.
Almost surely, 2131020010402 is an apocalyptic number.
131020010402 is a deficient number, since it is larger than the sum of its proper divisors (65510005204).
131020010402 is an equidigital number, since it uses as much as digits as its factorization.
131020010402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65510005203.
The product of its (nonzero) digits is 48, while the sum is 14.
Adding to 131020010402 its reverse (204010020131), we get a palindrome (335030030533).
The spelling of 131020010402 in words is "one hundred thirty-one billion, twenty million, ten thousand, four hundred two".
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