131020140044111 has 4 divisors (see below), whose sum is σ = 131022111435072. Its totient is φ = 131018168653152.

The previous prime is 131020140044107. The next prime is 131020140044141. The reversal of 131020140044111 is 111440041020131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131020140044111 - 2² = 131020140044107 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131020140044141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 985595786 + ... + 985728711.

It is an arithmetic number, because the mean of its divisors is an integer number (32755527858768).

Almost surely, 2^{131020140044111} is an apocalyptic number.

131020140044111 is a deficient number, since it is larger than the sum of its proper divisors (1971390961).

131020140044111 is an equidigital number, since it uses as much as digits as its factorization.

131020140044111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1971390960.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 131020140044111 its reverse (111440041020131), we get a palindrome (242460181064242).

The spelling of 131020140044111 in words is "one hundred thirty-one trillion, twenty billion, one hundred forty million, forty-four thousand, one hundred eleven".