Base | Representation |
---|---|
bin | 10011000100001110001… |
… | …000000010000111011001 |
3 | 11122020212020020100212221 |
4 | 103010032020002013121 |
5 | 132431243203341441 |
6 | 2441522024104041 |
7 | 163442012231062 |
oct | 23041610020731 |
9 | 4566766210787 |
10 | 1310202012121 |
11 | 465720973972 |
12 | 191b14005021 |
13 | 967228c49c2 |
14 | 475b2495569 |
15 | 241348d88d1 |
hex | 1310e2021d9 |
1310202012121 has 8 divisors (see below), whose sum is σ = 1311534379584. Its totient is φ = 1308870073680.
The previous prime is 1310202012109. The next prime is 1310202012127. The reversal of 1310202012121 is 1212102020131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1310202012121 - 25 = 1310202012089 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1310202012095 and 1310202012104.
It is not an unprimeable number, because it can be changed into a prime (1310202012127) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6190711 + ... + 6398851.
It is an arithmetic number, because the mean of its divisors is an integer number (163941797448).
Almost surely, 21310202012121 is an apocalyptic number.
It is an amenable number.
1310202012121 is a deficient number, since it is larger than the sum of its proper divisors (1332367463).
1310202012121 is a wasteful number, since it uses less digits than its factorization.
1310202012121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 214511.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 1310202012121 its reverse (1212102020131), we get a palindrome (2522304032252).
The spelling of 1310202012121 in words is "one trillion, three hundred ten billion, two hundred two million, twelve thousand, one hundred twenty-one".
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