Base | Representation |
---|---|
bin | 11000011001111000… |
… | …01111110110000111 |
3 | 1020211002202200100221 |
4 | 30030330033312013 |
5 | 203313104201043 |
6 | 10004033445211 |
7 | 642452230636 |
oct | 141474176607 |
9 | 36732680327 |
10 | 13102022023 |
11 | 5613828082 |
12 | 2657a10807 |
13 | 130a57296c |
14 | 8c412551d |
15 | 51a3a58ed |
hex | 30cf0fd87 |
13102022023 has 4 divisors (see below), whose sum is σ = 13106702448. Its totient is φ = 13097341600.
The previous prime is 13102021993. The next prime is 13102022029. The reversal of 13102022023 is 32022020131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13102022023 - 217 = 13101890951 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13102021988 and 13102022006.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13102022029) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2336011 + ... + 2341612.
It is an arithmetic number, because the mean of its divisors is an integer number (3276675612).
Almost surely, 213102022023 is an apocalyptic number.
13102022023 is a deficient number, since it is larger than the sum of its proper divisors (4680425).
13102022023 is an equidigital number, since it uses as much as digits as its factorization.
13102022023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4680424.
The product of its (nonzero) digits is 144, while the sum is 16.
Adding to 13102022023 its reverse (32022020131), we get a palindrome (45124042154).
The spelling of 13102022023 in words is "thirteen billion, one hundred two million, twenty-two thousand, twenty-three".
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