Base | Representation |
---|---|
bin | 1011111010101000110101… |
… | …1011010110100010001010 |
3 | 1201101112121111210110010212 |
4 | 2332222031123112202022 |
5 | 3204130420342313232 |
6 | 43510553011441122 |
7 | 2521406226026462 |
oct | 276521533264212 |
9 | 51345544713125 |
10 | 13102023010442 |
11 | 41a159a469553 |
12 | 1577314bb61a2 |
13 | 74069163a952 |
14 | 3341d9a10ba2 |
15 | 17ac312cbeb2 |
hex | bea8d6d688a |
13102023010442 has 4 divisors (see below), whose sum is σ = 19653034515666. Its totient is φ = 6551011505220.
The previous prime is 13102023010429. The next prime is 13102023010463. The reversal of 13102023010442 is 24401032020131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 6684763711081 + 6417259299361 = 2585491^2 + 2533231^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3275505752609 + ... + 3275505752612.
Almost surely, 213102023010442 is an apocalyptic number.
13102023010442 is a deficient number, since it is larger than the sum of its proper divisors (6551011505224).
13102023010442 is an equidigital number, since it uses as much as digits as its factorization.
13102023010442 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6551011505223.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 13102023010442 its reverse (24401032020131), we get a palindrome (37503055030573).
The spelling of 13102023010442 in words is "thirteen trillion, one hundred two billion, twenty-three million, ten thousand, four hundred forty-two".
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