| Base | Representation |
|---|---|
| bin | 10011000100001110001… |
| … | …001001011110100010000 |
| 3 | 11122020212020210200222122 |
| 4 | 103010032021023310100 |
| 5 | 132431243243022000 |
| 6 | 2441522034353412 |
| 7 | 163442014626146 |
| oct | 23041611136420 |
| 9 | 4566766720878 |
| 10 | 1310202314000 |
| 11 | 46572105a758 |
| 12 | 191b1412b868 |
| 13 | 9672299c228 |
| 14 | 475b2533596 |
| 15 | 24134948085 |
| hex | 1310e24bd10 |
1310202314000 has 320 divisors, whose sum is σ = 3406236986880. Its totient is φ = 486210560000.
The previous prime is 1310202313991. The next prime is 1310202314009. The reversal of 1310202314000 is 4132020131.
It is an interprime number because it is at equal distance from previous prime (1310202313991) and next prime (1310202314009).
It is a super-2 number, since 2×13102023140002 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1310202314000.
It is not an unprimeable number, because it can be changed into a prime (1310202314009) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 337592060 + ... + 337595940.
It is an arithmetic number, because the mean of its divisors is an integer number (10644490584).
Almost surely, 21310202314000 is an apocalyptic number.
1310202314000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1310202314000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1703118493440).
1310202314000 is an abundant number, since it is smaller than the sum of its proper divisors (2096034672880).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1310202314000 is a wasteful number, since it uses less digits than its factorization.
1310202314000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4147 (or 4131 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 1310202314000 its reverse (4132020131), we get a palindrome (1314334334131).
The spelling of 1310202314000 in words is "one trillion, three hundred ten billion, two hundred two million, three hundred fourteen thousand".
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