Base | Representation |
---|---|
bin | 1011111010101000110111… |
… | …0111010001110110100111 |
3 | 1201101112122000120101110212 |
4 | 2332222031313101312213 |
5 | 3204130424231100203 |
6 | 43510553432410035 |
7 | 2521406345200214 |
oct | 276521567216647 |
9 | 51345560511425 |
10 | 13102030331303 |
11 | 41a15a3609851 |
12 | 157731754691b |
13 | 740693001c14 |
14 | 3341da998b0b |
15 | 17ac31c761d8 |
hex | bea8ddd1da7 |
13102030331303 has 4 divisors (see below), whose sum is σ = 13144707954840. Its totient is φ = 13059352707768.
The previous prime is 13102030331297. The next prime is 13102030331311. The reversal of 13102030331303 is 30313303020131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13102030331303 - 26 = 13102030331239 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13102030331323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21338811308 + ... + 21338811921.
It is an arithmetic number, because the mean of its divisors is an integer number (3286176988710).
Almost surely, 213102030331303 is an apocalyptic number.
13102030331303 is a deficient number, since it is larger than the sum of its proper divisors (42677623537).
13102030331303 is an equidigital number, since it uses as much as digits as its factorization.
13102030331303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 42677623536.
The product of its (nonzero) digits is 1458, while the sum is 23.
Adding to 13102030331303 its reverse (30313303020131), we get a palindrome (43415333351434).
The spelling of 13102030331303 in words is "thirteen trillion, one hundred two billion, thirty million, three hundred thirty-one thousand, three hundred three".
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