Base | Representation |
---|---|
bin | 1011111010101000111000… |
… | …0010010011111000101011 |
3 | 1201101112122020000022102120 |
4 | 2332222032002103320223 |
5 | 3204130431001120321 |
6 | 43510554014402323 |
7 | 2521406411603352 |
oct | 276521602237053 |
9 | 51345566008376 |
10 | 13102033223211 |
11 | 41a15a5204559 |
12 | 15773185003a3 |
13 | 7406937a52ca |
14 | 3341db10c999 |
15 | 17ac32147ec6 |
hex | bea8e093e2b |
13102033223211 has 4 divisors (see below), whose sum is σ = 17469377630952. Its totient is φ = 8734688815472.
The previous prime is 13102033223207. The next prime is 13102033223231. The reversal of 13102033223211 is 11232233020131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13102033223211 - 22 = 13102033223207 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13102033223231) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2183672203866 + ... + 2183672203871.
It is an arithmetic number, because the mean of its divisors is an integer number (4367344407738).
Almost surely, 213102033223211 is an apocalyptic number.
13102033223211 is a deficient number, since it is larger than the sum of its proper divisors (4367344407741).
13102033223211 is an equidigital number, since it uses as much as digits as its factorization.
13102033223211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4367344407740.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 13102033223211 its reverse (11232233020131), we get a palindrome (24334266243342).
The spelling of 13102033223211 in words is "thirteen trillion, one hundred two billion, thirty-three million, two hundred twenty-three thousand, two hundred eleven".
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