Base | Representation |
---|---|
bin | 1011111010101000111010… |
… | …1011111011110000100001 |
3 | 1201101112122222112122210220 |
4 | 2332222032223323300201 |
5 | 3204130441244300213 |
6 | 43510555044313253 |
7 | 2521406603416452 |
oct | 276521653736041 |
9 | 51345588478726 |
10 | 13102044134433 |
11 | 41a16003872a1 |
12 | 15773200a2829 |
13 | 740695b25857 |
14 | 3341dc74d129 |
15 | 17ac330a0e23 |
hex | bea8eafbc21 |
13102044134433 has 16 divisors (see below), whose sum is σ = 17532074261760. Its totient is φ = 8703403756416.
The previous prime is 13102044134359. The next prime is 13102044134437. The reversal of 13102044134433 is 33443144020131.
It is not a de Polignac number, because 13102044134433 - 217 = 13102044003361 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13102044134394 and 13102044134403.
It is not an unprimeable number, because it can be changed into a prime (13102044134437) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5011785 + ... + 7163942.
It is an arithmetic number, because the mean of its divisors is an integer number (1095754641360).
Almost surely, 213102044134433 is an apocalyptic number.
It is an amenable number.
13102044134433 is a deficient number, since it is larger than the sum of its proper divisors (4430030127327).
13102044134433 is a wasteful number, since it uses less digits than its factorization.
13102044134433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12177016.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 13102044134433 its reverse (33443144020131), we get a palindrome (46545188154564).
The spelling of 13102044134433 in words is "thirteen trillion, one hundred two billion, forty-four million, one hundred thirty-four thousand, four hundred thirty-three".
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