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13102044134433 = 340987712175727
BaseRepresentation
bin1011111010101000111010…
…1011111011110000100001
31201101112122222112122210220
42332222032223323300201
53204130441244300213
643510555044313253
72521406603416452
oct276521653736041
951345588478726
1013102044134433
1141a16003872a1
1215773200a2829
13740695b25857
143341dc74d129
1517ac330a0e23
hexbea8eafbc21

13102044134433 has 16 divisors (see below), whose sum is σ = 17532074261760. Its totient is φ = 8703403756416.

The previous prime is 13102044134359. The next prime is 13102044134437. The reversal of 13102044134433 is 33443144020131.

It is not a de Polignac number, because 13102044134433 - 217 = 13102044003361 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13102044134394 and 13102044134403.

It is not an unprimeable number, because it can be changed into a prime (13102044134437) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5011785 + ... + 7163942.

It is an arithmetic number, because the mean of its divisors is an integer number (1095754641360).

Almost surely, 213102044134433 is an apocalyptic number.

It is an amenable number.

13102044134433 is a deficient number, since it is larger than the sum of its proper divisors (4430030127327).

13102044134433 is a wasteful number, since it uses less digits than its factorization.

13102044134433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12177016.

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 13102044134433 its reverse (33443144020131), we get a palindrome (46545188154564).

The spelling of 13102044134433 in words is "thirteen trillion, one hundred two billion, forty-four million, one hundred thirty-four thousand, four hundred thirty-three".

Divisors: 1 3 409 877 1227 2631 358693 1076079 12175727 36527181 4979872343 10678112579 14939617029 32034337737 4367348044811 13102044134433