13102044244033 has 8 divisors (see below), whose sum is σ = 13286779781760. Its totient is φ = 12917314253760.

The previous prime is 13102044244021. The next prime is 13102044244049. The reversal of 13102044244033 is 33044244020131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13102044244033 - 2²⁹ = 13101507373121 is a prime.

It is a super-2 number, since 2×13102044244033² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13102044243986 and 13102044244004.

It is not an unprimeable number, because it can be changed into a prime (13102044244013) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3490116 + ... + 6195562.

It is an arithmetic number, because the mean of its divisors is an integer number (1660847472720).

Almost surely, 2^{13102044244033} is an apocalyptic number.

It is an amenable number.

13102044244033 is a deficient number, since it is larger than the sum of its proper divisors (184735537727).

13102044244033 is an equidigital number, since it uses as much as digits as its factorization.

13102044244033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2773727.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 13102044244033 its reverse (33044244020131), we get a palindrome (46146288264164).

The spelling of 13102044244033 in words is "thirteen trillion, one hundred two billion, forty-four million, two hundred forty-four thousand, thirty-three".