Base | Representation |
---|---|
bin | 1011111010101000111010… |
… | …1100010110100001010001 |
3 | 1201101112122222202020011202 |
4 | 2332222032230112201101 |
5 | 3204130441311302144 |
6 | 43510555050520545 |
7 | 2521406604354155 |
oct | 276521654264121 |
9 | 51345588666152 |
10 | 13102044244049 |
11 | 41a1600451692 |
12 | 1577320136155 |
13 | 740695b63707 |
14 | 3341dc77b065 |
15 | 17ac330c364e |
hex | bea8eb16851 |
13102044244049 has 2 divisors, whose sum is σ = 13102044244050. Its totient is φ = 13102044244048.
The previous prime is 13102044244021. The next prime is 13102044244123. The reversal of 13102044244049 is 94044244020131.
13102044244049 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12028882919824 + 1073161324225 = 3468268^2 + 1035935^2 .
It is a cyclic number.
It is not a de Polignac number, because 13102044244049 - 228 = 13101775808593 is a prime.
It is not a weakly prime, because it can be changed into another prime (13102044247049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551022122024 + 6551022122025.
It is an arithmetic number, because the mean of its divisors is an integer number (6551022122025).
Almost surely, 213102044244049 is an apocalyptic number.
It is an amenable number.
13102044244049 is a deficient number, since it is larger than the sum of its proper divisors (1).
13102044244049 is an equidigital number, since it uses as much as digits as its factorization.
13102044244049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 110592, while the sum is 38.
The spelling of 13102044244049 in words is "thirteen trillion, one hundred two billion, forty-four million, two hundred forty-four thousand, forty-nine".
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