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13102045243003 = 71593311190301
BaseRepresentation
bin1011111010101000111011…
…0000001010011001111011
31201101112200001121222111001
42332222032300022121323
53204130442040234003
643510555124145431
72521406616014443
oct276521660123173
951345601558431
1013102045243003
1141a1600a74172
121577320538277
13740696123302
143341dc95b123
1517ac3321e61d
hexbea8ec0a67b

13102045243003 has 8 divisors (see below), whose sum is σ = 13308986835936. Its totient is φ = 12895726032000.

The previous prime is 13102045242997. The next prime is 13102045243013. The reversal of 13102045243003 is 30034254020131.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13102045243003 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13102045243013) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 155553048 + ... + 155637253.

It is an arithmetic number, because the mean of its divisors is an integer number (1663623354492).

Almost surely, 213102045243003 is an apocalyptic number.

13102045243003 is a deficient number, since it is larger than the sum of its proper divisors (206941592933).

13102045243003 is an equidigital number, since it uses as much as digits as its factorization.

13102045243003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 311190965.

The product of its (nonzero) digits is 8640, while the sum is 28.

Adding to 13102045243003 its reverse (30034254020131), we get a palindrome (43136299263134).

The spelling of 13102045243003 in words is "thirteen trillion, one hundred two billion, forty-five million, two hundred forty-three thousand, three".

Divisors: 1 71 593 42103 311190301 22094511371 184535848493 13102045243003