Search a number
-
+
13102110011 = 23653872369
BaseRepresentation
bin11000011001111001…
…00101010100111011
31020211002221011001202
430030330211110323
5203313120010021
610004035404415
7642453045314
oct141474452473
936732834052
1013102110011
1156138881a1
122657a5370b
13130a5a3a23
148c414960b
1551a3c1a0b
hex30cf2553b

13102110011 has 8 divisors (see below), whose sum is σ = 13692719520. Its totient is φ = 12513246592.

The previous prime is 13102109987. The next prime is 13102110023. The reversal of 13102110011 is 11001120131.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13102110011 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13102109974 and 13102110001.

It is not an unprimeable number, because it can be changed into a prime (13102112011) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 421166 + ... + 451203.

It is an arithmetic number, because the mean of its divisors is an integer number (1711589940).

Almost surely, 213102110011 is an apocalyptic number.

13102110011 is a deficient number, since it is larger than the sum of its proper divisors (590609509).

13102110011 is an equidigital number, since it uses as much as digits as its factorization.

13102110011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 873045.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 13102110011 its reverse (11001120131), we get a palindrome (24103230142).

The spelling of 13102110011 in words is "thirteen billion, one hundred two million, one hundred ten thousand, eleven".

Divisors: 1 23 653 15019 872369 20064487 569656957 13102110011