13102112202013 has 4 divisors (see below), whose sum is σ = 13102381006528. Its totient is φ = 13101843397500.

The previous prime is 13102112201999. The next prime is 13102112202029. The reversal of 13102112202013 is 31020221120131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13102112202013 is a prime.

It is a super-3 number, since 3×13102112202013³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13102112202083) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 134329131 + ... + 134426632.

It is an arithmetic number, because the mean of its divisors is an integer number (3275595251632).

Almost surely, 2^{13102112202013} is an apocalyptic number.

It is an amenable number.

13102112202013 is a deficient number, since it is larger than the sum of its proper divisors (268804515).

13102112202013 is an equidigital number, since it uses as much as digits as its factorization.

13102112202013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 268804514.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 13102112202013 its reverse (31020221120131), we get a palindrome (44122333322144).

The spelling of 13102112202013 in words is "thirteen trillion, one hundred two billion, one hundred twelve million, two hundred two thousand, thirteen".