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13102120000103 = 56344215263961
BaseRepresentation
bin1011111010101001001100…
…1101010101101001100111
31201101112212021022000221112
42332222103031111221213
53204131120210000403
643511010354335235
72521411514313251
oct276522315255147
951345767260845
1013102120000103
1141a163a1942a2
12157734158a51b
137406a8769194
1433420885acd1
1517ac39a899d8
hexbea93355a67

13102120000103 has 8 divisors (see below), whose sum is σ = 13128363339696. Its totient is φ = 13075887198400.

The previous prime is 13102120000037. The next prime is 13102120000201. The reversal of 13102120000103 is 30100002120131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13102120000103 - 28 = 13102119999847 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13102120000003) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 142958 + ... + 5121003.

It is an arithmetic number, because the mean of its divisors is an integer number (1641045417462).

Almost surely, 213102120000103 is an apocalyptic number.

13102120000103 is a deficient number, since it is larger than the sum of its proper divisors (26243339593).

13102120000103 is an equidigital number, since it uses as much as digits as its factorization.

13102120000103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5268945.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 13102120000103 its reverse (30100002120131), we get a palindrome (43202122120234).

The spelling of 13102120000103 in words is "thirteen trillion, one hundred two billion, one hundred twenty million, one hundred three", and thus it is an aban number.

Divisors: 1 563 4421 2489023 5263961 2963610043 23271971581 13102120000103