Base | Representation |
---|---|
bin | 1011111010101001001101… |
… | …0101011001100100110101 |
3 | 1201101112212102021101202022 |
4 | 2332222103111121210311 |
5 | 3204131121230111313 |
6 | 43511010511522525 |
7 | 2521411541264261 |
oct | 276522325314465 |
9 | 51345772241668 |
10 | 13102122113333 |
11 | 41a16403a7a70 |
12 | 1577342229445 |
13 | 7406a9029006 |
14 | 334208c4b0a1 |
15 | 17ac39d55c08 |
hex | bea93559935 |
13102122113333 has 4 divisors (see below), whose sum is σ = 14293224123648. Its totient is φ = 11911020103020.
The previous prime is 13102122113231. The next prime is 13102122113357. The reversal of 13102122113333 is 33331122120131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13102122113333 - 214 = 13102122096949 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13102122112333) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 595551005141 + ... + 595551005162.
It is an arithmetic number, because the mean of its divisors is an integer number (3573306030912).
Almost surely, 213102122113333 is an apocalyptic number.
It is an amenable number.
13102122113333 is a deficient number, since it is larger than the sum of its proper divisors (1191102010315).
13102122113333 is a wasteful number, since it uses less digits than its factorization.
13102122113333 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1191102010314.
The product of its (nonzero) digits is 1944, while the sum is 26.
Adding to 13102122113333 its reverse (33331122120131), we get a palindrome (46433244233464).
The spelling of 13102122113333 in words is "thirteen trillion, one hundred two billion, one hundred twenty-two million, one hundred thirteen thousand, three hundred thirty-three".
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