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13102123011 = 34367374337
BaseRepresentation
bin11000011001111001…
…01000100000000011
31020211002221210220020
430030330220200003
5203313120414021
610004035544523
7642453131235
oct141474504003
936732853806
1013102123011
115613896a3a
122657a5b143
13130a5a9913
148c4150255
1551a3c57c6
hex30cf28803

13102123011 has 4 divisors (see below), whose sum is σ = 17469497352. Its totient is φ = 8734748672.

The previous prime is 13102123009. The next prime is 13102123081. The reversal of 13102123011 is 11032120131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13102123011 - 21 = 13102123009 is a prime.

It is a super-2 number, since 2×131021230112 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13102123081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2183687166 + ... + 2183687171.

It is an arithmetic number, because the mean of its divisors is an integer number (4367374338).

Almost surely, 213102123011 is an apocalyptic number.

13102123011 is a deficient number, since it is larger than the sum of its proper divisors (4367374341).

13102123011 is an equidigital number, since it uses as much as digits as its factorization.

13102123011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4367374340.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 13102123011 its reverse (11032120131), we get a palindrome (24134243142).

The spelling of 13102123011 in words is "thirteen billion, one hundred two million, one hundred twenty-three thousand, eleven".

Divisors: 1 3 4367374337 13102123011