Base | Representation |
---|---|
bin | 11000011001111001… |
… | …01010100011110010 |
3 | 1020211002222020110111 |
4 | 30030330222203302 |
5 | 203313121201232 |
6 | 10004040051534 |
7 | 642453164641 |
oct | 141474524362 |
9 | 36732866414 |
10 | 13102131442 |
11 | 56138a2304 |
12 | 2657a63baa |
13 | 130a5b06ca |
14 | 8c4153358 |
15 | 51a3c8047 |
hex | 30cf2a8f2 |
13102131442 has 4 divisors (see below), whose sum is σ = 19653197166. Its totient is φ = 6551065720.
The previous prime is 13102131437. The next prime is 13102131443. The reversal of 13102131442 is 24413120131.
13102131442 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 24413120131 = 1979 ⋅12336089.
It can be written as a sum of positive squares in only one way, i.e., 12964327321 + 137804121 = 113861^2 + 11739^2 .
It is not an unprimeable number, because it can be changed into a prime (13102131443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3275532859 + ... + 3275532862.
Almost surely, 213102131442 is an apocalyptic number.
13102131442 is a deficient number, since it is larger than the sum of its proper divisors (6551065724).
13102131442 is an equidigital number, since it uses as much as digits as its factorization.
13102131442 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6551065723.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 13102131442 its reverse (24413120131), we get a palindrome (37515251573).
The spelling of 13102131442 in words is "thirteen billion, one hundred two million, one hundred thirty-one thousand, four hundred forty-two".
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