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13102200231 = 34367400077
BaseRepresentation
bin11000011001111001…
…11011010110100111
31020211010002201211020
430030330323112213
5203313130401411
610004041342223
7642453602331
oct141474732647
936733081736
1013102200231
115613939a5a
122657a97973
13130a605b03
148c4170451
1551a3dd606
hex30cf3b5a7

13102200231 has 4 divisors (see below), whose sum is σ = 17469600312. Its totient is φ = 8734800152.

The previous prime is 13102200211. The next prime is 13102200239. The reversal of 13102200231 is 13200220131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13102200231 - 219 = 13101675943 is a prime.

It is a super-2 number, since 2×131022002312 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13102200231.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13102200239) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2183700036 + ... + 2183700041.

It is an arithmetic number, because the mean of its divisors is an integer number (4367400078).

Almost surely, 213102200231 is an apocalyptic number.

13102200231 is a deficient number, since it is larger than the sum of its proper divisors (4367400081).

13102200231 is an equidigital number, since it uses as much as digits as its factorization.

13102200231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4367400080.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 13102200231 its reverse (13200220131), we get a palindrome (26302420362).

The spelling of 13102200231 in words is "thirteen billion, one hundred two million, two hundred thousand, two hundred thirty-one".

Divisors: 1 3 4367400077 13102200231