Search a number
-
+
13102211131020 = 22325112627195929
BaseRepresentation
bin1011111010101001100010…
…1000111110011010001100
31201101120002121202222001200
42332222120220332122030
53204131312022143040
643511023411505500
72521414002026124
oct276523050763214
951346077688050
1013102211131020
1141a1686678300
121577367bb8290
137406c15c5abb
143342169bdc84
1517ac42a8b630
hexbea98a3e68c

13102211131020 has 216 divisors, whose sum is σ = 43692287009280. Its totient is φ = 3175753996800.

The previous prime is 13102211131007. The next prime is 13102211131091. The reversal of 13102211131020 is 2013111220131.

13102211131020 is a `hidden beast` number, since 1 + 310 + 2 + 21 + 1 + 1 + 310 + 20 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 13102211130984 and 13102211131002.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 136534416 + ... + 136630344.

Almost surely, 213102211131020 is an apocalyptic number.

13102211131020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13102211131020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21846143504640).

13102211131020 is an abundant number, since it is smaller than the sum of its proper divisors (30590075878260).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13102211131020 is a wasteful number, since it uses less digits than its factorization.

13102211131020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 102237 (or 102221 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 13102211131020 its reverse (2013111220131), we get a palindrome (15115322351151).

It can be divided in two parts, 13102211 and 131020, that added together give a palindrome (13233231).

The spelling of 13102211131020 in words is "thirteen trillion, one hundred two billion, two hundred eleven million, one hundred thirty-one thousand, twenty".