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13102222001 = 111191111091
BaseRepresentation
bin11000011001111010…
…00000101010110001
31020211010010211200112
430030331000222301
5203313132101001
610004042031105
7642454022651
oct141475005261
936733124615
1013102222001
115613954350
122657aa8495
13130a6129ab
148c4178361
1551a3e4cbb
hex30cf40ab1

13102222001 has 4 divisors (see below), whose sum is σ = 14293333104. Its totient is φ = 11911110900.

The previous prime is 13102221983. The next prime is 13102222037. The reversal of 13102222001 is 10022220131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13102222001 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (13102122001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 595555535 + ... + 595555556.

It is an arithmetic number, because the mean of its divisors is an integer number (3573333276).

Almost surely, 213102222001 is an apocalyptic number.

13102222001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13102222001 is a deficient number, since it is larger than the sum of its proper divisors (1191111103).

13102222001 is a wasteful number, since it uses less digits than its factorization.

13102222001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1191111102.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 13102222001 its reverse (10022220131), we get a palindrome (23124442132).

The spelling of 13102222001 in words is "thirteen billion, one hundred two million, two hundred twenty-two thousand, one".

Divisors: 1 11 1191111091 13102222001