13102300313122 has 4 divisors (see below), whose sum is σ = 19653450469686. Its totient is φ = 6551150156560.

The previous prime is 13102300313101. The next prime is 13102300313153. The reversal of 13102300313122 is 22131300320131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 9673400023681 + 3428900289441 = 3110209^2 + 1851729^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13102300313093 and 13102300313102.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3275575078279 + ... + 3275575078282.

Almost surely, 2^{13102300313122} is an apocalyptic number.

13102300313122 is a deficient number, since it is larger than the sum of its proper divisors (6551150156564).

13102300313122 is an equidigital number, since it uses as much as digits as its factorization.

13102300313122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6551150156563.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 13102300313122 its reverse (22131300320131), we get a palindrome (35233600633253).

The spelling of 13102300313122 in words is "thirteen trillion, one hundred two billion, three hundred million, three hundred thirteen thousand, one hundred twenty-two".