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1310231130314 = 22447267721931
BaseRepresentation
bin10011000100001111110…
…111000111000011001010
311122020221021000201112112
4103010033313013003022
5132431323132132224
62441524544142322
7163442514564551
oct23041767070312
94566837021475
101310231130314
11465736351897
12191b219079a2
139672894b4c2
14475b62b4d98
152413723b30e
hex1310fdc70ca

1310231130314 has 8 divisors (see below), whose sum is σ = 1966149868608. Its totient is φ = 654847840780.

The previous prime is 1310231130301. The next prime is 1310231130337. The reversal of 1310231130314 is 4130311320131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×13102311303142 (a number of 25 digits) contains 22 as substring.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 1310231130314.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 133856072 + ... + 133865859.

It is an arithmetic number, because the mean of its divisors is an integer number (245768733576).

Almost surely, 21310231130314 is an apocalyptic number.

1310231130314 is a deficient number, since it is larger than the sum of its proper divisors (655918738294).

1310231130314 is a wasteful number, since it uses less digits than its factorization.

1310231130314 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 267724380.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 1310231130314 its reverse (4130311320131), we get a palindrome (5440542450445).

The spelling of 1310231130314 in words is "one trillion, three hundred ten billion, two hundred thirty-one million, one hundred thirty thousand, three hundred fourteen".

Divisors: 1 2 2447 4894 267721931 535443862 655115565157 1310231130314