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1310231202122 = 2655115601061
BaseRepresentation
bin10011000100001111110…
…111011000100101001010
311122020221021011101001002
4103010033313120211022
5132431323141431442
62441524545455002
7163442515314113
oct23041767304512
94566837141032
101310231202122
114657363a0837
12191b21941462
13967289750ab
14475b62d320a
1524137252732
hex1310fdd894a

1310231202122 has 4 divisors (see below), whose sum is σ = 1965346803186. Its totient is φ = 655115601060.

The previous prime is 1310231202089. The next prime is 1310231202127. The reversal of 1310231202122 is 2212021320131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1279163262001 + 31067940121 = 1131001^2 + 176261^2 .

It is a super-2 number, since 2×13102312021222 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1310231202094 and 1310231202103.

It is not an unprimeable number, because it can be changed into a prime (1310231202127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 327557800529 + ... + 327557800532.

Almost surely, 21310231202122 is an apocalyptic number.

1310231202122 is a deficient number, since it is larger than the sum of its proper divisors (655115601064).

1310231202122 is an equidigital number, since it uses as much as digits as its factorization.

1310231202122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 655115601063.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 1310231202122 its reverse (2212021320131), we get a palindrome (3522252522253).

The spelling of 1310231202122 in words is "one trillion, three hundred ten billion, two hundred thirty-one million, two hundred two thousand, one hundred twenty-two".

Divisors: 1 2 655115601061 1310231202122