131023121433 has 4 divisors (see below), whose sum is σ = 174697495248. Its totient is φ = 87348747620.

The previous prime is 131023121431. The next prime is 131023121473. The reversal of 131023121433 is 334121320131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131023121433 - 2¹ = 131023121431 is a prime.

It is not an unprimeable number, because it can be changed into a prime (131023121431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21837186903 + ... + 21837186908.

It is an arithmetic number, because the mean of its divisors is an integer number (43674373812).

Almost surely, 2^131023121433 is an apocalyptic number.

It is an amenable number.

131023121433 is a deficient number, since it is larger than the sum of its proper divisors (43674373815).

131023121433 is an equidigital number, since it uses as much as digits as its factorization.

131023121433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43674373814.

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 131023121433 its reverse (334121320131), we get a palindrome (465144441564).

The spelling of 131023121433 in words is "one hundred thirty-one billion, twenty-three million, one hundred twenty-one thousand, four hundred thirty-three".