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131023535 = 526204707
BaseRepresentation
bin1111100111101…
…00001010101111
3100010112200111112
413303310022233
5232020223120
621000142235
73150452546
oct763641257
9303480445
10131023535
1167a60a15
1237a6797b
13211b6626
141358915d
15b781bc5
hex7cf42af

131023535 has 4 divisors (see below), whose sum is σ = 157228248. Its totient is φ = 104818824.

The previous prime is 131023523. The next prime is 131023553. The reversal of 131023535 is 535320131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131023535 - 212 = 131019439 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131023535.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13102349 + ... + 13102358.

It is an arithmetic number, because the mean of its divisors is an integer number (39307062).

Almost surely, 2131023535 is an apocalyptic number.

131023535 is a deficient number, since it is larger than the sum of its proper divisors (26204713).

131023535 is an equidigital number, since it uses as much as digits as its factorization.

131023535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26204712.

The product of its (nonzero) digits is 1350, while the sum is 23.

The square root of 131023535 is about 11446.5512273348. The cubic root of 131023535 is about 507.9057203569.

Adding to 131023535 its reverse (535320131), we get a palindrome (666343666).

The spelling of 131023535 in words is "one hundred thirty-one million, twenty-three thousand, five hundred thirty-five".

Divisors: 1 5 26204707 131023535