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1310240040503 = 17630112231859
BaseRepresentation
bin10011000100010000011…
…001000110011000110111
311122020221212210102000112
4103010100121012120313
5132431332422244003
62441525503133235
7163442653405022
oct23042031063067
94566855712015
101310240040503
11465740388189
12191b248a421b
139672a74acc4
14475b75541b9
1524137deb3d8
hex13110646637

1310240040503 has 8 divisors (see below), whose sum is σ = 1387533270960. Its totient is φ = 1232971286400.

The previous prime is 1310240040457. The next prime is 1310240040517. The reversal of 1310240040503 is 3050400420131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1310240040503 - 224 = 1310223263287 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310240040533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6008813 + ... + 6223046.

It is an arithmetic number, because the mean of its divisors is an integer number (173441658870).

Almost surely, 21310240040503 is an apocalyptic number.

1310240040503 is a deficient number, since it is larger than the sum of its proper divisors (77293230457).

1310240040503 is a wasteful number, since it uses less digits than its factorization.

1310240040503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12238177.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 1310240040503 its reverse (3050400420131), we get a palindrome (4360640460634).

The spelling of 1310240040503 in words is "one trillion, three hundred ten billion, two hundred forty million, forty thousand, five hundred three".

Divisors: 1 17 6301 107117 12231859 207941603 77072943559 1310240040503